<\/span>L\u00f4 4 c\u00e0ng \u0103n bao nhi\u00eau?<\/h3>\n\u0110i\u1ec1u m\u00e0 anh em quan t\u00e2m nhi\u1ec1u nh\u1ea5t ch\u1eafc ch\u1eafn l\u00e0 ti\u1ec1n \u0103n con l\u00f4 4 c\u00e0ng l\u00e0 bao nhi\u00eau? Anh em y\u00ean t\u00e2m v\u00ec c\u00e1ch \u0111\u00e1nh n\u00e0y ch\u1eafn ch\u1eafn s\u1ebd c\u00f3 t\u1ef7 l\u1ec7 ti\u1ec1n th\u01b0\u1edfng r\u1ea5t cao v\u00e0 h\u1ea5p d\u1eabn, nh\u01b0ng \u0111\u1ed5i l\u1ea1i l\u00e0 x\u00e1c su\u1ea5t tr\u00fang c\u0169ng kh\u00f4ng h\u1ec1 d\u1ec5 d\u00e0ng.<\/p>\n
N\u1ebfu nh\u01b0 t\u1ef7 l\u1ec7 \u0103n \u0111\u1ec1 4 c\u00e0ng l\u00e0 0.01%, \u0111\u1ec1 3 c\u00e0ng l\u00e0 0.1%, th\u00ec \u0103n l\u00f4 4 s\u1ebd r\u01a1i v\u00e0o kho\u1ea3ng g\u1ea7n 0.2%<\/p>\n
\u1ede m\u1ed7i m\u1ed9t nh\u00e0 c\u00e1i\/ch\u1ee7 l\u00f4 \u0111\u1ec1 s\u1ebd quy \u0111\u1ecbnh ti\u1ec1n \u0103n l\u00f4 4 kh\u00e1c nhau. Th\u00f4ng th\u01b0\u1eddng th\u00ec t\u1ef7 l\u1ec7 n\u00e0y r\u01a1i v\u00e0o kho\u1ea3ng 1 \u0103n 8880 ho\u1eb7c 1 \u0103n 9000, v\u1edbi s\u1ed1 ti\u1ec1n v\u1ed1n b\u1ecf ra ban \u0111\u1ea7u th\u1ea5p nh\u1ea5t ch\u1ec9 l\u00e0 1.000 vn\u0111.<\/p>\n
Ti\u1ec1n v\u1ed1n = S\u1ed1 ti\u1ec1n \u0111\u1eb7t c\u01b0\u1ee3c 1 con X s\u1ed1 l\u01b0\u1ee3ng con l\u00f4 \u0111\u00e1nh.<\/strong><\/p>\nTi\u1ec1n th\u01b0\u1edfng = Ti\u1ec1n v\u1ed1n X 8880 X (S\u1ed1 con tr\u00fang + s\u1ed1 nh\u00e1y n\u1ed5 m\u1ed7i con).<\/strong><\/p>\nTi\u1ec1n l\u1eddi = Ti\u1ec1n th\u01b0\u1edfng \u2013 ti\u1ec1n v\u1ed1n.<\/strong><\/p>\nV\u00ed d\u1ee5: Anh em \u0111\u00e1nh 10.000 vn\u0111 cho con 2612 v\u00e0 1458, chi\u1ec1u h\u00f4m \u0111\u00f3 con 2612 v\u00e0 1458 \u0111\u1ec1u tr\u00fang 1 nh\u00e1y th\u00ec s\u1ed1 ti\u1ec1n th\u01b0\u1edfng c\u1ee7a anh em theo c\u00f4ng th\u1ee9c ph\u00eda tr\u00ean s\u1ebd l\u00e0 20.000 X 8880 X 2 = 355.200.000 vn\u0111.<\/p>\n
V\u1eady s\u1ed1 ti\u1ec1n m\u00e0 anh em th\u1ef1c nh\u1eadn s\u1ebd l\u00e0 355.200.000 \u2013 20.000 = 355.180.000 vn\u0111. M\u1ed9t s\u1ed1 ti\u1ec1n qu\u00e1 cao n\u1ebfu anh em tr\u00fang \u0111\u01b0\u1ee3c con l\u00f4 4.<\/p>\n
\u0110\u00e2y ch\u1ec9 l\u00e0 c\u00e1ch t\u00ednh ti\u1ec1n tr\u00fang khi t\u1ef7 l\u1ec7 l\u00e0 1 \u0103n 8880, c\u00f3 nh\u1eefng nh\u00e0 c\u00e1i v\u1edbi t\u1ef7 l\u1ec7 \u0103n l\u00e0 1 \u0103n 9000 th\u00ec s\u1ed1 ti\u1ec1n th\u1ef1c t\u1ebf nh\u1eadn n\u00e0y s\u1ebd cao h\u01a1n nhi\u1ec1u.<\/p>\n
<\/p>\n
L\u00f4 b\u1ed1n c\u00e0ng \u0103n bao nhi\u00eau?<\/p>\n<\/div>\n
<\/span>T\u1ed5ng h\u1ee3p c\u00e1ch b\u1eaft 4 c\u00e0ng hi\u1ec7u qu\u1ea3 nh\u1ea5t<\/h2>\nD\u00f9 l\u00e0 b\u1ed1n c\u00e0ng<\/strong>, nh\u01b0ng c\u00e1ch soi c\u1ea7u b\u1eaft s\u1ed1 l\u00e0 kh\u00e1c nhau. T\u00f4i xin t\u1ed5ng h\u1ee3p c\u00e1c c\u00e1ch b\u1eaft l\u00f4 \u0111\u1ec1 4 c\u00e0ng hi\u1ec7u qu\u1ea3 nh\u1ea5t b\u00ean d\u01b0\u1edbi. C\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n<\/span>I. C\u00e1ch \u0111\u00e1nh \u0111\u1ec1 4 c\u00e0ng<\/h3>\nN\u1ebfu nh\u01b0 t\u1ef7 l\u1ec7 \u0111o\u00e1n tr\u00fang c\u1ee7a ch\u01a1i \u0111\u1ec1 truy\u1ec1n th\u1ed1ng l\u00e0 1\/100, \u0111\u1ec1 3 c\u00e0ng kh\u00f3 h\u01a1n l\u00e0 1\/1000, th\u00ec \u0111\u1ec3 b\u1eaft \u0111\u01b0\u1ee3c con \u0111\u1ec1 4 c\u00e0ng s\u1ebd l\u00e0 1\/10000 t\u01b0\u01a1ng \u0111\u01b0\u01a1ng v\u1edbi 0.01%. V\u1edbi m\u1ee9c ti\u1ec1n th\u01b0\u1edfng cao ng\u1ea5t ng\u01b0\u1ee1ng m\u00e0 c\u00e1c nh\u00e0 c\u00e1i h\u1ea5p d\u1eabn anh em th\u00ec t\u1ef7 l\u1ec7 tr\u00fang th\u1ea5p c\u0169ng l\u00e0 \u0111i\u1ec1u \u0111\u01b0\u01a1ng nhi\u00ean.<\/p>\n
V\u1eady n\u00ean, anh em c\u1ea7n ph\u1ea3i c\u00f3 cho m\u00ecnh nh\u1eefng b\u00ed quy\u1ebft ho\u1eb7c kinh nghi\u1ec7m ch\u01a1i l\u00f4 \u0111\u1ec1 l\u00e2u n\u0103m thay v\u00ec ch\u1ec9 \u0111o\u00e1n b\u1eeba theo qu\u00e1n t\u00ednh.<\/p>\n
<\/span>1. Ph\u01b0\u01a1ng ph\u00e1p b\u1eaft t\u1ed5ng \u0111\u1ec1 4 ng\u00e0y<\/h4>\nC\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1ec1 4 ng\u00e0y l\u00e0 m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p b\u1eaft c\u00e0ng 4 chu\u1ea9n x\u00e1c c\u1ee7a m\u1ed9t tay d\u00e2n ch\u01a1i mi\u1ec1n B\u1eafc 3 l\u1ea7n li\u00ean t\u1ee5c th\u1eafng \u0111\u1ec1 4 c\u00e0ng.<\/p>\n
D\u00e2n ch\u01a1i m\u1ecdi n\u01a1i lan truy\u1ec1n nhau v\u1ec1 c\u00e1ch \u0111\u00e1nh n\u00e0y v\u00e0 t\u1ea5t nhi\u00ean r\u1eb1ng \u0111\u00e2y l\u00e0 m\u1ed9t c\u00e1ch \u0111\u00e1nh hi\u1ec7u qu\u1ea3 th\u00ec m\u1edbi \u0111\u01b0\u1ee3c lan r\u1ed9ng \u0111\u1ebfn nh\u01b0 v\u1eady. C\u00e1c chuy\u00ean gia l\u00f4 \u0111\u1ec1 c\u1ee7a ch\u00fang t\u00f4i c\u0169ng \u0111\u00e1nh gi\u00e1 cao ph\u01b0\u01a1ng ph\u00e1p n\u00e0y. C\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
T\u1ed5ng \u0111\u1ec1 (ng\u00e0y 1 + ng\u00e0y 2 + ng\u00e0y 3 + ng\u00e0y 4) => CON \u0110\u1ec0 4 C\u00c0NG.<\/p>\n
V\u00ed d\u1ee5: Anh em mu\u1ed1n \u0111\u00e1nh \u0111\u1ec1 4 c\u00e0ng ng\u00e0y th\u1ee9 7, anh em xem th\u1ed1ng k\u00ea \u0111\u1ec1 \u0111\u1eb7c bi\u1ec7t c\u1ee7a c\u00e1c ng\u00e0y v\u1ec1 tr\u01b0\u1edbc:<\/p>\n
\n- Ng\u00e0y th\u1ee9 3: X\u1ed5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t Mi\u1ec1n B\u1eafc l\u00e0 41512 \u2013 12: T\u1ed5ng \u0111\u1ec1 1 + 2 = 3.<\/li>\n
- Ng\u00e0y th\u1ee9 4: X\u1ed5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 12771 \u2013 71: T\u1ed5ng \u0111\u1ec1 7 + 1 = 8.<\/li>\n
- Ng\u00e0y th\u1ee9 5: X\u1ed5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 54193 \u2013 93: T\u1ed5ng \u0111\u1ec1 9 + 3 = 2.<\/li>\n
- Ng\u00e0y th\u1ee9 6: X\u1ed5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 47156 \u2013 56: T\u1ed5ng \u0111\u1ec1 5 + 6 = 1.<\/li>\n<\/ul>\n
Theo ph\u01b0\u01a1ng ph\u00e1p ta c\u00f3 con 4 c\u00e0ng \u0111\u00e1nh ng\u00e0y th\u1ee9 7 l\u00e0: 3 8 2 1.<\/strong><\/p>\nL\u01b0u \u00fd: Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y th\u01b0\u1eddng ch\u1ec9 c\u00f3 hi\u1ec7u qu\u1ea3 v\u00e0o th\u1ee9 7 v\u00e0 ch\u1ee7 nh\u1eadt, anh em l\u01b0u \u00fd.<\/p>\n
<\/span>2. Ph\u01b0\u01a1ng ph\u00e1p b\u1eaft \u0111\u1ec1 theo t\u1ed5ng ng\u00e0y\/ th\u00e1ng v\u00e0 con b\u1ea1ch th\u1ee7<\/h4>\nPh\u01b0\u01a1ng ph\u00e1p n\u00e0y l\u00e0 kinh nghi\u1ec7m ch\u01a1i l\u00f4 \u0111\u1ec1 c\u1ee7a h\u01a1n 30 anh em l\u00f4 th\u1ee7 trong su\u1ed1t h\u01a1n 5 n\u0103m qua v\u1edbi t\u1ef7 l\u1ec7 tr\u00fang h\u01a1n 30%. \u0110\u01b0\u01a1ng nhi\u00ean l\u00e0 t\u1eeb 0.01% l\u00ean \u0111\u01b0\u1ee3c 30% th\u00ec c\u0169ng l\u00e0 m\u1ed9t v\u1ea5n \u0111\u1ec1 kh\u00f4ng h\u1ec1 \u0111\u01a1n gi\u1ea3n.<\/p>\n
V\u00ed d\u1ee5: H\u00f4m nay l\u00e0 ng\u00e0y 22\/11 => T\u1ed5ng ng\u00e0y + th\u00e1ng = 22 + 11 = 33.<\/p>\n
Sau \u0111\u00f3 anh em l\u1ea5y 3 + 3 = 6. V\u1edbi 6 l\u00e0 t\u1ed5ng c\u1ee7a c\u00e1c con s\u1ed1 nh\u01b0 06 \u2013 60 \u2013 15 \u2013 51 \u2013 24 \u2013 42 \u2013 33.<\/p>\n
Gi\u1ea3 s\u1eed con b\u1ea1ch th\u1ee7 \u0111\u1ec1 c\u1ee7a anh em ng\u00e0y h\u00f4m nay l\u00e0 51 th\u00ec anh em c\u00f3 th\u1ec3 \u0111\u00e1nh nh\u01b0 sau: 0651 \u2013 6051 \u2013 1551 \u2013 5151 \u2013 2451 \u2013 4251 \u2013 3351.<\/p>\n
C\u00e1ch t\u00ecm con b\u1ea1ch th\u1ee7 l\u00f4 th\u00ec c\u0169ng t\u00f9y v\u00e0o t\u1eebng anh em. Nhi\u1ec1u anh em nu\u00f4i s\u1ed1 ho\u1eb7c ch\u1ecdn ngay con \u0111\u1ec1 ra ng\u00e0y h\u00f4m tr\u01b0\u1edbc \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y h\u00f4m nay.<\/p>\n
<\/p>\n
<\/span>3. Ph\u01b0\u01a1ng ph\u00e1p soi ng\u0169 h\u00e0nh b\u00f3ng l\u00f4 \u0111\u1ec1<\/h4>\nV\u00ed d\u1ee5: Con b\u1ea1ch th\u1ee7 c\u1ee7a anh em t\u00ednh to\u00e1n \u0111\u01b0\u1ee3c trong ng\u00e0y h\u00f4m nay l\u00e0 27, th\u00ec anh em s\u1ebd c\u00f3 c\u00f4ng th\u1ee9c nh\u01b0 sau:<\/p>\n
B\u00f3ng \u00e2m \u0111\u1ea7u con b\u1ea1ch th\u1ee7 + b\u00f3ng d\u01b0\u01a1ng \u0111u\u00f4i con b\u1ea1ch th\u1ee7 + b\u1ea1ch th\u1ee7 \u0111\u1ec1.<\/p>\n
\u1ede \u0111\u00e2y con 27 g\u1ed3m 2 con s\u1ed1 2 v\u00e0 7. Ch\u00fang ta ph\u00e2n t\u00edch \u0111\u01b0\u1ee3c: B\u00f3ng \u00e2m c\u1ee7a 2 l\u00e0 9, b\u00f3ng d\u01b0\u01a1ng c\u1ee7a 7 l\u00e0 2. V\u1eady ta gh\u00e9p l\u1ea1i \u0111\u01b0\u1ee3c con 92.<\/p>\n
V\u1eady con \u0111\u1ec1 4 c\u00e0ng c\u1ee7a anh em s\u1ebd l\u00e0: 9 2 2 7<\/strong><\/p>\nL\u01b0u \u00fd: Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u1ec9 c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng 1 tu\u1ea7n 2 ng\u00e0y, c\u00f3 th\u1ec3 r\u01a1i v\u00e0o 2 ng\u00e0y \u0111\u1ea7u tu\u1ea7n ho\u1eb7c 2 ng\u00e0y cu\u1ed1i tu\u1ea7n.<\/p>\n
<\/span>II. B\u00ed quy\u1ebft b\u1eaft con l\u00f4 4 c\u00e0ng hi\u1ec7u qu\u1ea3<\/h3>\nT\u1ef7 l\u1ec7 tr\u00fang th\u1ea5p \u0111\u1ed3ng ngh\u0129a v\u1edbi vi\u1ec7c anh em kh\u00f4ng th\u1ec3 ch\u1ec9 d\u1ef1a v\u00e0o may m\u1eafn. \u0110\u1ec3 th\u1eafng, anh em c\u1ea7n ph\u1ea3i c\u00f3 ph\u01b0\u01a1ng ph\u00e1p \u0111\u00e1nh v\u00e0 c\u00e1ch soi c\u1ea7u l\u00f4 4 c\u00e0ng<\/strong> hi\u1ec7u qu\u1ea3.<\/p>\nM\u1eddi anh em c\u00f9ng t\u00ecm hi\u1ec3u qua nh\u1eefng c\u00e1ch b\u00ean d\u01b0\u1edbi.<\/p>\n
<\/span>1. Theo d\u00f5i \u0111\u1ec1 v\u1ec1 trong 3 ng\u00e0y tr\u01b0\u1edbc<\/h4>\nAnh em c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng c\u00e1ch th\u1ee9c n\u00e0y b\u1eb1ng c\u00e1ch theo d\u00f5i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t t\u1eeb KQXS h\u1eb1ng ng\u00e0y. Anh em c\u00f3 th\u1ec3 soi c\u1ea7u tr\u01b0\u1edbc 2 ng\u00e0y \u0111\u1ec3 c\u00f3 th\u1ec3 t\u00ednh \u0111\u01b0\u1ee3c con l\u00f4 4 n\u00e0o s\u1ebd c\u00f3 t\u1ef7 l\u1ec7 ra cao nh\u1ea5t trong ng\u00e0y th\u1ee9 3.<\/p>\n
N\u1ebfu nh\u01b0 k\u1ebft qu\u1ea3 c\u1ee7a ng\u00e0y th\u1ee9 3 v\u1ec1 c\u00f3 s\u1ed1 \u0111\u1ea7u ho\u1eb7c s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y th\u1ee9 1 v\u00e0 2, th\u00ec vi\u1ec7c c\u00f2n l\u1ea1i anh em c\u1ea7n ph\u1ea3i l\u00e0m ch\u1ec9 l\u00e0 ph\u00e1n \u0111o\u00e1n con b\u1ea1ch th\u1ee7 m\u00e0 anh em \u0111\u00e3 k\u1ebft sau th\u1eddi gian d\u00e0i v\u00e0 gh\u00e9p l\u1ea1i \u0111\u1ec3 \u0111\u00e1nh con l\u00f4 4.<\/p>\n
<\/span>2. D\u00e0n \u0111\u1ec1 gi\u1ea3i 5<\/h4>\n\u0110\u00e2y l\u00e0 c\u00e1ch \u0111\u00e1nh m\u00e0 anh em c\u1ea7n soi r\u00f5 2 con s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a c\u00e1c gi\u1ea3i 5. Sau \u0111\u00f3 gh\u00e9p t\u1eebng c\u1eb7p v\u1edbi c\u00e1c s\u1ed1 trong gi\u1ea3i 5.3 \u0111\u1ec3 t\u1ea1o th\u00e0nh con 4 c\u00e0ng chu\u1ea9n.<\/p>\n
\u0110\u00e2y c\u00f3 th\u1ec3 n\u00f3i l\u00e0 m\u1ed9t c\u00e1ch \u0111\u00e1nh theo kinh nghi\u1ec7m c\u1ee7a c\u00e1c b\u1eadc ti\u1ec1n b\u1ed1i truy\u1ec1n l\u1ea1i m\u00e0 ch\u1ec9 c\u00f3 nh\u1eefng anh em l\u00f4 th\u1ee7 kinh nghi\u1ec7m l\u00e2u n\u0103m m\u1edbi bi\u1ebft. Tuy nhi\u00ean, \u0111\u00e2y c\u0169ng l\u00e0 m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p v\u00f4 c\u00f9ng hi\u1ec7u qu\u1ea3.<\/p>\n
<\/span>3. Soi b\u00f3ng c\u1ee7a gi\u1ea3i 3<\/h4>\nC\u00e1c h\u00ecnh th\u1ee9c kh\u00e1c c\u00f3 c\u00e1ch b\u1eaft b\u00f3ng l\u00f4 hi\u1ec7u qu\u1ea3 \u1edf gi\u1ea3i 3 th\u00ec l\u00f4 4 c\u00e0ng c\u0169ng th\u1ebf. T\u1ef7 l\u1ec7 \u0111\u00e1nh ch\u1ea1m \u0111\u1ec1 \u0103n theo b\u00f3ng l\u00f4 ng\u00e0y h\u00f4m sau c\u0169ng v\u00f4 c\u00f9ng hi\u1ec7u qu\u1ea3.<\/p>\n
Anh em c\u1ea7n l\u00ean k\u1ebf ho\u1ea1ch c\u0169ng nh\u01b0 chi\u1ebfn l\u01b0\u1ee3c ph\u00f9 h\u1ee3p \u0111\u1ec3 ch\u1ecdn cho m\u00ecnh m\u1ed9t con s\u1ed1 c\u00f3 t\u1ef7 l\u1ec7 v\u1ec1 cao nh\u1ea5t trong ng\u00e0y h\u00f4m nay.<\/p>\n
<\/p>\n
B\u00f3ng \u00e2m c\u1ee7a c\u00e1c con s\u1ed1 nh\u01b0 sau:<\/strong><\/h4>\n\n- B\u00f3ng \u00e2m s\u1ed1 1 l\u00e0 s\u1ed1 4.<\/li>\n
- B\u00f3ng \u00e2m s\u1ed1 2 l\u00e0 s\u1ed1 9.<\/li>\n
- B\u00f3ng \u00e2m s\u1ed1 3 l\u00e0 s\u1ed1 6.<\/li>\n
- B\u00f3ng \u00e2m s\u1ed1 5 l\u00e0 s\u1ed1 8.<\/li>\n
- B\u00f3ng \u00e2m s\u1ed1 0 l\u00e0 s\u1ed1 7.<\/li>\n<\/ul>\n
B\u00f3ng d\u01b0\u01a1ng c\u1ee7a c\u00e1c con s\u1ed1 nh\u01b0 sau:<\/strong><\/h4>\n\n- B\u00f3ng d\u01b0\u01a1ng s\u1ed1 1 l\u00e0 s\u1ed1 6.<\/li>\n
- B\u00f3ng d\u01b0\u01a1ng s\u1ed1 2 l\u00e0 s\u1ed1 7.<\/li>\n
- B\u00f3ng d\u01b0\u01a1ng s\u1ed1 3 l\u00e0 s\u1ed1 8.<\/li>\n
- B\u00f3ng d\u01b0\u01a1ng s\u1ed1 4 l\u00e0 s\u1ed1 9.<\/li>\n
- B\u00f3ng d\u01b0\u01a1ng s\u1ed1 5 l\u00e0 s\u1ed1 0.<\/li>\n<\/ul>\n
<\/span>\u0110\u00fac k\u1ebft<\/h2>\nL\u00f4 v\u00e0 \u0111\u1ec1 4 c\u00e0ng<\/strong> l\u00e0 2 h\u00ecnh th\u1ee9c \u0111\u00e1nh l\u00f4 \u0111\u1ec1<\/span> c\u1ef1c k\u1ef3 kh\u00f3 c\u0169ng nh\u01b0 c\u00f3 m\u1ee9c ti\u1ec1n th\u01b0\u1edfng v\u00f4 c\u00f9ng cao.<\/p>\nSau b\u00e0i ph\u00e2n t\u00edch tr\u00ean, t\u00f4i c\u00f3 m\u1ed9t s\u1ed1 \u0111\u00fac k\u1ebft sau:<\/p>\n
\n- T\u00ednh \u0111\u01b0\u1ee3c 4 c\u00e0ng Mi\u1ec1n B\u1eafc \u0103n bao nhi\u00eau<\/strong>, c\u00e1ch \u0111\u00e1nh v\u00e0 kh\u00e1i ni\u1ec7m.<\/li>\n
- Anh em n\u00ean theo d\u00f5i, th\u1ed1ng k\u00ea v\u00e0 nu\u00f4i nhi\u1ec1u con l\u00f4 \u0111\u1ec1 m\u00e0 anh em cho l\u00e0 c\u00f3 x\u00e1c su\u1ea5t n\u1ed5 cao \u0111\u1ec3 \u0111\u00e1nh c\u00f9ng l\u00fac, n\u00e2ng cao t\u1ef7 l\u1ec7 tr\u00fang.<\/li>\n
- H\u00ecnh th\u1ee9c ch\u01a1i l\u00f4 \u0111\u1ec1 n\u00e0y l\u00e0 r\u1ea5t kh\u00f3 v\u1edbi t\u1ef7 l\u1ec7 tr\u00fang c\u1ef1c th\u1ea5p, \u0111\u1ed5i l\u1ea1i l\u00e0 s\u1ed1 v\u1ed1n anh em b\u1ecf ra c\u00f3 th\u1ec3 l\u00e0 kh\u00f4ng cao nh\u01b0ng m\u1ee9c ti\u1ec1n th\u01b0\u1edfng \u0111\u1ed5i l\u1ea1i l\u00e0 r\u1ea5t nhi\u1ec1u.<\/li>\n
- Gi\u1eef v\u1eefng t\u00e2m l\u00fd: Kh\u00f4ng mang t\u00e2m l\u00fd g\u1ee1 v\u1ed1n v\u00e0 lu\u00f4n n\u00e2ng cao kinh nghi\u1ec7m c\u1ee7a b\u1ea3n th\u00e2n thay v\u00ec \u0111\u1ed1t ti\u1ec1n m\u00e0 kh\u00f4ng suy ngh\u0129. N\u1ebfu nh\u01b0 v\u1eady s\u1ebd \u1ea3nh h\u01b0\u1edfng r\u1ea5t nhi\u1ec1u \u0111\u1ebfn cu\u1ed9c s\u1ed1ng, gia \u0111\u00ecnh v\u00e0 c\u00f4ng vi\u1ec7c c\u1ee7a anh em.<\/li>\n<\/ul>\n
H\u00e3y lu\u00f4n ch\u01a1i l\u00f4 \u0111\u1ec1 m\u1ed9t c\u00e1ch t\u00edch c\u1ef1c nh\u1ea5t, ch\u00fac anh em may m\u1eafn v\u00e0 th\u00e0nh c\u00f4ng.<\/p>\n<\/article>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n