<\/span>1. C\u1ed9ng d\u1ed3n gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u00e1c ng\u00e0y tr\u01b0\u1edbc \u0111\u00f3<\/h3>\n\u0110\u00e2y l\u00e0 c\u00e1ch \u0111\u00e1nh l\u00f4 t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t kh\u00e1 ch\u00ednh x\u00e1c, v\u00e0 d\u00e0nh cho anh em bi\u1ebft ki\u00ean nh\u1eabn.<\/p>\n
Anh em s\u1ebd thi\u1ebft l\u1eadp d\u00e0n l\u00f4 b\u1eb1ng c\u00e1ch c\u1ed9ng d\u1ed3n gi\u1ea3i \u0111\u1eb7c bi\u1ec7t t\u1eeb tu\u1ea7n tr\u01b0\u1edbc. C\u00e1ch l\u1eadp d\u00e0n n\u00e0y s\u1ebd cho anh em kho\u1ea3ng 10 c\u1eb7p l\u00f4 \u0111\u1ec3 nu\u00f4i trong v\u00f2ng 1 tu\u1ea7n, l\u00f4 n\u00e0o ra r\u1ed3i c\u00f3 th\u1ec3 nu\u00f4i ti\u1ebfp. L\u01b0u \u00fd: N\u1ebfu t\u1ed5ng l\u1edbn h\u01a1n 10 th\u00ec ch\u1ec9 l\u1ea5y s\u1ed1 \u1edf h\u00e0ng \u0111\u01a1n v\u1ecb, t\u1ed5ng b\u1eb1ng 10 t\u00ednh l\u00e0 0.<\/p>\n
V\u00ed d\u1ee5 nh\u00e9: Ta c\u00f3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a KQXSMB c\u00e1c ng\u00e0y t\u1eeb 16\/11 \u2013 22\/11\/2024 l\u1ea7n l\u01b0\u1ee3t ph\u00eda d\u01b0\u1edbi. Ta s\u1ebd t\u00ednh t\u1ed5ng c\u1ee7a t\u1eebng gi\u1ea3i v\u00e0 t\u00ecm ra nh\u1eefng con t\u1ed5ng ch\u01b0a v\u1ec1. R\u1ed3i t\u1eeb \u0111\u00f3 thi\u1ebft l\u1eadp d\u00e0n l\u00f4 \u0111\u1eb9p \u0111\u1ec3 nu\u00f4i trong v\u00f2ng 1 tu\u1ea7n.<\/p>\n
Anh em nu\u00f4i d\u00e0n l\u00f4 \u0111\u1ec1 t\u1eeb ph\u01b0\u01a1ng ph\u00e1p b\u1eaft t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t n\u00e0y trong v\u00f2ng 1 tu\u1ea7n nh\u00e9.<\/p>\n
Anh em n\u00ean truy c\u1eadp c\u00e1c trang c\u00f3 b\u1ea3ng th\u1ed1ng k\u00ea b\u1ea3ng \u0111\u1eb7c bi\u1ec7t theo t\u1ed5ng \u0111\u1ec3 xem c\u00e1c l\u00f4 gan ch\u01b0a v\u1ec1 trong v\u00f2ng 1 tu\u1ea7n n\u1eefa \u0111\u1ec3 \u0111\u1ed1i chi\u1ebfu.<\/p>\n
R\u1ed3i \u00e1p d\u1ee5ng th\u00eam kinh nghi\u1ec7m b\u1ea3n th\u00e2n m\u00e0 gi\u1eef, hay lo\u1ea1i con l\u00f4 \u0111\u1ec1 n\u00e0o m\u00e0 anh em mu\u1ed1n nh\u00e9. T\u1ed1t nh\u1ea5t l\u00e0 anh em ph\u1ea3i bi\u1ebft kinh nghi\u1ec7m nu\u00f4i l\u00f4 khung 7 ng\u00e0y \u0111\u00e3, r\u1ed3i h\u00e3y th\u1ef1c chi\u1ebfn.<\/p>\n
N\u1ebfu mu\u1ed1n nhanh g\u1ecdn, anh em c\u00f3 th\u1ec3 l\u00e0 t\u1ed5ng \u0111\u1ec1 ng\u00e0y h\u00f4m qua \u0111\u1ec3 l\u00e0m c\u1eb7p song th\u1ee7 l\u00f4 \u0111\u00e1nh cho ng\u00e0y mai. Anh em s\u1ebd ng\u1ea1c nhi\u00ean v\u1edbi t\u1ef7 l\u1ec7 tr\u00fang c\u1ee7a n\u00f3 \u0111\u1ea5y.<\/p>\n
<\/span>2. D\u1ef1a v\u00e0o d\u1eef li\u1ec7u c\u1ee7a gi\u1ea3i 7<\/h3>\nAnh em c\u1ee9 l\u1ea5y t\u1ed5ng c\u1ee7a c\u1eb7p s\u1ed1 th\u1ee9 hai c\u1ee7a gi\u1ea3i 7 v\u00e0o ng\u00e0y th\u1ee9 7. V\u00e0 nu\u00f4i n\u00f3 trong v\u00f2ng 2-3 ng\u00e0y.<\/p>\n
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Ta c\u00f3 t\u1ed5ng l\u00e0 9 r\u1ed3i. C\u00f3 th\u1ec3 l\u1ea5y ngay n\u00f3 l\u00e0m con b\u1ea1ch th\u1ee7 l\u00f4 l\u00e0 g\u00ec m\u00e0 \u0111\u1eadp cho ng\u00e0y mai. Ho\u1eb7c anh em ch\u01a1i song th\u1ee7 09 \u2013 90 \u0111\u1ec3 nu\u00f4i trong tu\u1ea7n. C\u00f2n n\u1ebfu t\u1ed5ng l\u1edbn h\u01a1n 10. Vd nh\u01b0 8 + 7 = 15 th\u00ec anh em l\u1ea5y 1 + 5 v\u00e0 1 \u2013 5. Ta \u0111\u01b0\u1ee3c 2 con t\u1ed5ng \u0111\u1ec1 l\u00e0 6 v\u00e0 4 \u0111\u1ec3 nu\u00f4i.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p t\u1ed5ng \u0111\u1ec1 n\u00e0y r\u1ea5t nhanh g\u1ecdn, k\u1ebft qu\u1ea3 cho ngay trong tu\u1ea7n cho c\u00e1c anh em c\u1ee9ng tay v\u00e0 m\u00e1u l\u1eeda. C\u00f3 th\u1ec3 \u00e1p d\u1ee5ng cho c\u1ea3 Mi\u1ec1n Nam v\u00e0 Mi\u1ec1n B\u1eafc.<\/p>\n
<\/span>3. Tuy\u1ec7t chi\u00eau tam gi\u00e1c Pascal<\/h3>\nAnh em \u0111\u1eebng nh\u1ea7m l\u1eabn ph\u01b0\u01a1ng ph\u00e1p n\u00e0y v\u1edbi c\u00e1ch soi c\u1ea7u tam gi\u00e1c nh\u00e9. L\u1ea5y t\u1ed5ng Pascal c\u1ee7a Newton l\u00e0 m\u1ed9t \u1ee9ng d\u1ee5ng tuy\u1ec7t v\u1eddi \u0111\u1ec3 anh em nghi\u00ean c\u1ee9u x\u1ed5 s\u1ed1 c\u1ef1c chu\u1ea9n.<\/p>\n
\u00c1p d\u1ee5ng ki\u1ebfn th\u1ee9c to\u00e1n h\u1ecdc v\u00e0 c\u00e1ch \u0111\u00e1nh l\u00f4 gan, k\u00e8m th\u00eam t\u00ed kinh nghi\u1ec7m b\u1ea3n th\u00e2n v\u00e0 may m\u1eafn c\u1ee7a anh em l\u00e0 c\u00f3 th\u1ec3 \u0103n ngay con l\u00f4 \u0111\u1ec1 th\u01a1m nh\u1ea5t. Anh em l\u00e0m nh\u01b0 sau<\/p>\n
Anh em l\u1ea5y k\u1ebft qu\u1ea3 gi\u1ea3i th\u01b0\u1edfng \u0111\u1eb7c bi\u1ec7t v\u00e0 gi\u1ea3i nh\u1ea5t x\u1ed5 s\u1ed1 c\u1ee7a ng\u00e0y h\u00f4m qua. Vi\u1ebft th\u00e0nh 1 h\u00e0ng n\u1eb1m d\u01b0\u1edbi \u0111\u00e1y tam gi\u00e1c.<\/p>\n
V\u00ed d\u1ee5 gi\u1ea3i \u0110B l\u00e0 15315 v\u00e0 gi\u1ea3i nh\u1ea5t l\u00e0 75178. Anh em vi\u1ebft d\u00e3y 1 5 3 1 5 7 5 1 7 8 th\u00e0nh 1 h\u00e0ng n\u1eb1m d\u01b0\u1edbi \u0111\u00e1y tam gi\u00e1c. Sau \u0111\u00f3 \u00e1p d\u1ee5ng c\u00e1ch x\u00e2y d\u1ef1ng tam gi\u00e1c Pascal c\u1ee7a Newton, c\u1ee5 th\u1ec3:<\/p>\n
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C\u1ee9 l\u1ea5y 2 s\u1ed1 c\u1ed9ng v\u1edbi nhau theo th\u1ee9 t\u1ef1 t\u1eeb tr\u00e1i qua ph\u1ea3i, l\u1ea7n l\u01b0\u1ee3t ta s\u1ebd \u0111\u01b0\u1ee3c m\u1ed9t d\u00e3y s\u1ed1 m\u1edbi v\u00e0 \u0111i\u1ec1n l\u00ean h\u00e0ng th\u1ee9 2.<\/p>\n
1 + 5, 5 + 3, 3 + 1, 1 + 5, 5 + 7, 7 + 5, 5 + 1, 1 + 7, 7 + 8 ta \u0111\u01b0\u1ee3c h\u00e0ng th\u1ee9 2 l\u00e0: 6 8 4 6 2 2 6 8 5<\/p>\n<\/div>\n
C\u1ee9 l\u00e0m nh\u01b0 v\u1eady ti\u1ebfp t\u1ee5c d\u1ea7n d\u1ea7n ta s\u1ebd x\u00e2y d\u1ef1ng \u0111\u01b0\u1ee3c tam gi\u00e1c Pascal v\u00e0 qu\u1ea5t con b\u1ea1ch th\u1ee7 \u2013 2 s\u1ed1 c\u00f2n l\u1ea1i sau c\u00f9ng. Anh em xem h\u00ecnh b\u00ean d\u01b0\u1edbi nh\u00e9!<\/p>\n
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Ph\u01b0\u01a1ng ph\u00e1p b\u1eaft l\u00f4 v\u1edbi tam gi\u00e1c Pascal c\u1ee7a Newton.<\/p>\n<\/div>\n
Nh\u01b0 v\u1eady anh em c\u00f3 th\u1ec3 \u0111\u1eadp con 89 \u2013 98 l\u00e0m con b\u1ea1ch th\u1ee7 t\u00f9y \u00fd.<\/p>\n
Anh em ch\u1ec9 vi\u1ec7c truy c\u1eadp \u0111\u1ec3 xem th\u1ed1ng k\u00ea l\u00f4 gan, l\u00f4 gan c\u1ef1c \u0111\u1ea1i, c\u1ea7u l\u00f4 v\u1eefng ch\u1eafc\u2026. V\u1eadn d\u1ee5ng th\u00eam kinh nghi\u1ec7m c\u1ee7a anh em n\u1eefa l\u00e0 b\u1ea3o \u0111\u1ea3m anh em d\u1ec5 tr\u00fang \u0111\u1eadm v\u1edbi c\u00e1ch ch\u1ed1t l\u00f4 n\u00e0y \u0111\u1ea5y.<\/p>\n
<\/span>4. C\u00e1ch nh\u1ea3y c\u00f3c<\/h3>\n<\/p>\n
C\u0169ng b\u1ea3ng KQXS mi\u1ec1n B\u1eafc \u1edf tr\u00ean. Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t anh em c\u00f3 l\u00e0 7 5 1 7 8. Anh em ch\u1ec9 vi\u1ec7c c\u1ed9ng nh\u1ea3y c\u00f3c nh\u01b0 sau:<\/p>\n
Th\u1ebf l\u00e0 ta \u0111\u01b0\u1ee3c con b\u1ea1ch th\u1ee7 17 \u2013 71 t\u00f9y anh em. C\u00e1ch t\u00ednh t\u1ed5ng \u0111\u1ec1 nh\u1ea3y c\u00f3c n\u00e0y k\u1ebft h\u1ee3p v\u1edbi vi\u1ec7c ph\u00e2n t\u00edch th\u1ed1ng k\u00ea b\u1ea3ng \u0111\u1eb7c bi\u1ec7t theo t\u1ed5ng th\u00ec anh em s\u1ebd t\u0103ng kh\u1ea3 n\u0103ng chi\u1ebfn th\u1eafng c\u1ee7a m\u00ecnh l\u00ean \u0111\u00e1ng k\u1ec3 \u0111\u1ea5y.<\/p>\n
Ph\u1ed1i h\u1ee3p th\u00eam ki\u1ebfn th\u1ee9c c\u1ee7a anh em v\u1ec1 b\u00f3ng l\u00f4 \u0111\u1ec1 n\u1eefa \u0111\u1ec3 t\u0103ng \u0111\u1ed9 ch\u1eafc c\u1ee7a c\u1ea7u th\u00ec qu\u00e1 tuy\u1ec7t v\u1eddi.<\/p>\n
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B\u1eaft t\u1ed5ng nh\u1ea3y c\u00f3c th\u01b0\u1eddng \u0111\u01b0\u1ee3c d\u00e2n ch\u01a1i \u00e1p d\u1ee5ng \u1edf c\u00e1c \u0111\u00e0i XSMN hay c\u00f3 hi\u1ec7u qu\u1ea3.<\/p>\n<\/div>\n
<\/span>L\u1eddi khuy\u00ean<\/h2>\nTr\u00ean l\u00e0 m\u1ed9t s\u1ed1 c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1ec1 hi\u1ec7u qu\u1ea3 m\u00e0 t\u00f4i mu\u1ed1n chia s\u1ebb \u0111\u1ebfn v\u1edbi anh em. Anh em nh\u1edb, kh\u00f4ng ph\u1ea3i l\u00fac n\u00e0o c\u0169ng \u00e1p d\u1ee5ng \u0111\u01b0\u1ee3c m\u00e0 ph\u1ea3i linh \u0111\u1ed9ng ph\u01b0\u01a1ng ph\u00e1p, xem k\u0129 c\u00e1c c\u00e1ch ch\u1ed1t l\u00f4 hay.<\/p>\n
T\u1eeb \u0111\u00f3 \u00e1p d\u1ee5ng v\u1edbi kinh nghi\u1ec7m v\u00e0 ki\u1ebfn th\u1ee9c c\u1ee7a anh em m\u00e0 ch\u1ed1t s\u1ed1 cho th\u1eadt chu\u1ea9n. Ch\u00fac anh em \u0111\u00e1nh \u0111\u00e2u th\u1eafng \u0111\u00f3, t\u00e0i l\u1ed9c tri\u1ec1n mi\u00ean.<\/p>\n